Chapter 17 Measures of Central Tendency Ex 17.6

Rajasthan Board RBSE Class 10 Maths Chapter 17 Measures of Central Tendency Ex 17.6

Question 1.
Find median of the following variable values
25, 34, 33, 13, 20, 26, 36, 28, 19, 34
Solution :
Arranging given values is ascending order
13, 19, 20, 25, 26, 28, 33, 34, 34, 36
In given values. No. of terms n = 10 which is even No. Thus,
Rajasthan Board RBSE Class 10 Maths Chapter 17 Measures of Central Tendency Q1.1
Thus, median = 27
Question 2.
Find the median of the data
19, 25, 59, 48, 35, 31, 30, 32, 51
If 25 is replaced by 52, then find new median.
Solution :
Arranging given data in ascending order
19, 25, 30, 31, 32, 35, 48, 51, 59
Number of terms in given data, n =9 which is odd, thus
Rajasthan Board RBSE Class 10 Maths Chapter 17 Measures of Central Tendency Q2.1
In second case, when 25 is replaced by 52 then arranging data in ascending order
19, 30, 31, 32, 35, 48, 51, 52, 59
Rajasthan Board RBSE Class 10 Maths Chapter 17 Measures of Central Tendency Q2.2
Thus, first median 32
New median = 35 (after replacement)
Question 3.
Marks obtained by students in a class are given in following table. Find median.
Rajasthan Board RBSE Class 10 Maths Chapter 17 Measures of Central Tendency Q3.1
Solution :
Writing the distribution in tabulation form
Rajasthan Board RBSE Class 10 Maths Chapter 17 Measures of Central Tendency Q3.2
\frac { N }{ 2 }=\frac { 99 }{ 2 }=49.5
C.F. just above 49.5 is 52 whose corresponding variable value is 30.
∴ Required median = 30
Question 4.
Number of children in 100 families are as follows :
Rajasthan Board RBSE Class 10 Maths Chapter 17 Measures of Central Tendency Q4.1
Find their median.
Solution :
Rajasthan Board RBSE Class 10 Maths Chapter 17 Measures of Central Tendency Q4.2
Here \frac { N }{ 2 }=\frac { 100 }{ 2 }=50
C.F. just above 50 is 72 whose corresponding variable value is 2.
∴ Required median = 2
Question 5.
Find median of following frequency distribution :
Rajasthan Board RBSE Class 10 Maths Chapter 17 Measures of Central Tendency Q5.1
Solution :
Writing the distribution in tabulation form :
Rajasthan Board RBSE Class 10 Maths Chapter 17 Measures of Central Tendency Q5.2
Here \frac { N }{ 2 }=\frac { 160 }{ 2 }=80
C.F. just above 80 is 105 whose corresponding variable value is 35.
∴ Required median = 35

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