Rajasthan Board RBSE Class 10 Maths Chapter 17 Measures of Central Tendency Ex 17.7
Question 1.
Marks obtained by 100 students are given in the following table.
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Find their median.
Solution :
Preparing cumulative frequency table :
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Here
= 50
Cumulative frequency just above 50 is 70 whose corresponding class-interval is 40 – 50.
Thus, median class =40 – 50
∵ l = 40, f = 44, C = 26, h = 10
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Marks obtained by 100 students are given in the following table.

Find their median.
Solution :
Preparing cumulative frequency table :

Here
Cumulative frequency just above 50 is 70 whose corresponding class-interval is 40 – 50.
Thus, median class =40 – 50
∵ l = 40, f = 44, C = 26, h = 10

Question 2.
Marks obtained by students of a class are given in the following frequency distribution :

Find their median.
Solution :
Preparing cumulative frequency table :

Here
=
= 50
Cumulative frequency just above 50 is 74 whose corresponding class-interval is 20 – 30.
Thus, median class =20 – 30
∵ l = 20, f = 42, C = 32, h = 10

= 20 +
= 20 + 4.29 = 24.29
Thus, median class = 24.29
Marks obtained by students of a class are given in the following frequency distribution :

Find their median.
Solution :
Preparing cumulative frequency table :

Here
Cumulative frequency just above 50 is 74 whose corresponding class-interval is 20 – 30.
Thus, median class =20 – 30
∵ l = 20, f = 42, C = 32, h = 10

= 20 +
Thus, median class = 24.29
Find median from the following frequency distribution (Q.3 and 4)
Question 3.
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Solution :
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Here
=
= 50
Cumulative frequency just above 50 is 65 whose corresponding class-interval is 40 – 50.
Thus, median class =40 – 50
∵ l = 40, f = 30, C = 35, h = 10
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= 40 +
= 40 + 5 = 45
Thus, required median = 45
Question 3.
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Solution :
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Here
Cumulative frequency just above 50 is 65 whose corresponding class-interval is 40 – 50.
Thus, median class =40 – 50
∵ l = 40, f = 30, C = 35, h = 10

= 40 +
Thus, required median = 45
Question 4.
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Solution :
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Here
=
= 78.5
Cumulative frequency just above 78.5 is 122 whose corresponding class-interval is 16 – 24.
Thus, median class =16 – 24
∵ l = 16, f = 50, C = 72, h = 8
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= 16 +
= 16 + 1.04 = 17.04
Thus, median class = 17.04
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Solution :
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Here
Cumulative frequency just above 78.5 is 122 whose corresponding class-interval is 16 – 24.
Thus, median class =16 – 24
∵ l = 16, f = 50, C = 72, h = 8

= 16 +
Thus, median class = 17.04
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