Chapter 17 Measures of Central Tendency Ex 17.7

Rajasthan Board RBSE Class 10 Maths Chapter 17 Measures of Central Tendency Ex 17.7

Question 1.
Marks obtained by 100 students are given in the following table.
Rajasthan Board RBSE Class 10 Maths Chapter 17 Measures of Central Tendency Q1.1
Find their median.
Solution :
Preparing cumulative frequency table :
Rajasthan Board RBSE Class 10 Maths Chapter 17 Measures of Central Tendency Q1.2
Here \frac { N }{ 2 } = 50
Cumulative frequency just above 50 is 70 whose corresponding class-interval is 40 – 50.
Thus, median class =40 – 50
∵ l = 40, f = 44, C = 26, h = 10
Rajasthan Board RBSE Class 10 Maths Chapter 17 Measures of Central Tendency Q1.3
Question 2.
Marks obtained by students of a class are given in the following frequency distribution :
Rajasthan Board RBSE Class 10 Maths Chapter 17 Measures of Central Tendency Q2.1
Find their median.
Solution :
Preparing cumulative frequency table :
Rajasthan Board RBSE Class 10 Maths Chapter 17 Measures of Central Tendency Q2.2
Here \frac { N }{ 2 } = \frac { 100 }{ 2 } = 50
Cumulative frequency just above 50 is 74 whose corresponding class-interval is 20 – 30.
Thus, median class =20 – 30
∵ l = 20, f = 42, C = 32, h = 10
Rajasthan Board RBSE Class 10 Maths Chapter 17 Measures of Central Tendency Q2.3
= 20 + \frac { 180 }{ 42 } = 20 + 4.29 = 24.29
Thus, median class = 24.29
Find median from the following frequency distribution (Q.3 and 4)
Question 3.
Rajasthan Board RBSE Class 10 Maths Chapter 17 Measures of Central Tendency Q3.1
Solution :
Rajasthan Board RBSE Class 10 Maths Chapter 17 Measures of Central Tendency Q3.2
Here \frac { N }{ 2 } = \frac { 100 }{ 2 } = 50
Cumulative frequency just above 50 is 65 whose corresponding class-interval is 40 – 50.
Thus, median class =40 – 50
∵ l = 40, f = 30, C = 35, h = 10
Rajasthan Board RBSE Class 10 Maths Chapter 17 Measures of Central Tendency Q3.3
= 40 + \frac { 150 }{ 30 } = 40 + 5 = 45
Thus, required median = 45
Question 4.
Rajasthan Board RBSE Class 10 Maths Chapter 17 Measures of Central Tendency Q4.1
Solution :
Rajasthan Board RBSE Class 10 Maths Chapter 17 Measures of Central Tendency Q4.2
Here \frac { N }{ 2 } = \frac { 157 }{ 2 } = 78.5
Cumulative frequency just above 78.5 is 122 whose corresponding class-interval is 16 – 24.
Thus, median class =16 – 24
∵ l = 16, f = 50, C = 72, h = 8
Rajasthan Board RBSE Class 10 Maths Chapter 17 Measures of Central Tendency Q4.3
= 16 + \frac { 52 }{ 50 } = 16 + 1.04 = 17.04
Thus, median class = 17.04

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